Conditional Statements in C++ HackerRank Solution

Hello Programmers, In this post, you will know how to solve the Conditional Statements in C++ HackerRank Solution. This problem is a part of the HackerRank C++ Programming Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

Conditional Statements in C++ HackerRank Solution

Problem

if and else are two of the most frequently used conditionals in C/C++, and they enable you to execute zero or one conditional statement among many such dependent conditional statements. We use them in the following ways:
1. if: This executes the body of bracketed code starting with statement1 if condition evaluates to true.

if (condition) {
    statement1;
    ...
}

2. if – else: This executes the body of bracketed code starting with statement1 if condition evaluates to true, or it executes the body of code starting with statement2 if condition evaluates to false. Note that only one of the bracketed code sections will ever be executed.

if (condition) {
    statement1;
    ...
}
else {
    statement2;
    ...
}

3. if – else if – else: In this structure, dependent statements are chained together and the condition or each statement is only checked if all prior conditions in the chain evaluated to false. Once a condition evaluates to true, the bracketed code associated with that statement is executed and the program then skips to the end of the chain of statements and continues executing. If each condition in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.

if(first condition) {
    ...
}
else if(second condition) {
    ...
}
.
.
.
else if((n-1)'th condition) {
    ....
}
else {
    ...
}

Given a positive integer denoting n, do the following:

• If  1<=n<=9, then print the lowercase English word corresponding to the number(e.g one for 1, two for 2 etc)
• if n > 9 Then print Greater than 9 

Input Format

A single integer denoting n.

Constraints

• 1<=n<=10^9 

Output Format

If 1<=n<=9, then print the lowercase English word corresponding to the number(e.g one for 1, two for 2 etc), if n > 9 Then print Greater than 9.

Example 0 :

Sample Input 0

5

Sample Output 0

five

Explanation 0
five is the English word for the number 5.

Example 1 :

Sample Input 1

8

Sample Output 1

eight

Explanation 1
eight is the English word for the number 8.

Example 2 :

Sample Input 2

44

Sample Output 2

Greater than 9

Explanation 2
n = 44 is greater than 9, so we print Greater than 9.

report this adConditional Statements in C++ HackerRank Solution

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin >> n;
    cin.ignore(numeric_limits<streamsize>::max(), '\n');
    // Write Your Code Here
    if (n==1)
    cout<<"one";
    else if(n==2)
    cout<<"two";
    else if(n==3)
    cout<<"three";
    else if(n==4)
    cout<<"four";
    else if(n==5)
    cout<<"five";
    else if(n==6)
    cout<<"six";
    else if(n==7)
    cout<<"seven";
    else if(n==8)
    cout<<"eight";
    else if(n==9)
    cout<<"nine";
    else
    cout<<"Greater than 9";
    return 0;
}

Disclaimer: The above Problem (Conditional Statements in C++) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

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