Hello Programmers, In this post, you will know how to solve the HackerRank Bill Division Solution. This problem is a part of the HackerRank Algorithms Series.
One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.
HackerRank Bill Division Solution
Task
Two friends Anna and Brian, are deciding how to split the bill at a dinner. Each will only pay for the items they consume. Brian gets the check and calculates Anna’s portion. You must determine if his calculation is correct.
For example, assume the bill has the following prices: bill = [2, 4, 6]. Anna declines to eat item k = bill[2] which costs 6. If Brian calculates the bill correctly, Anna will pay (2 + 4)/2 = 3. If he includes the cost of bill[2], he will calculate (2 + 4 + 6)/2 = 6. In the second case, he should refund 3 to Anna.
Function Description
Complete the bonAppetit function in the editor below. It should print Bon Appetit if the bill is fairly split. Otherwise, it should print the integer amount of money that Brian owes Anna.
bonAppetit has the following parameter(s):
- bill: an array of integers representing the cost of each item ordered
- k: an integer representing the zero-based index of the item Anna doesn’t eat
- b: the amount of money that Anna contributed to the bill
Input Format
The first line contains two space-separated integers n and k, the number of items ordered and the 0-based index of the item that Anna did not eat.
The second line contains n space-separated integers bill[i] where 0 <= i < n.
The third line contains an integer, b, the amount of money that Brian charged Anna for her share of the bill.
Constraints
- 2 <= n <= 105
- 0 <= k < n
- 0 <= bill[i] <= 104
- 0 <= b <= bill[i]
- The amount of money due Anna will always be an integer
Output Format
If Brian did not overcharge Anna, print Bon Appetit on a new line; otherwise, print the difference (i.e., bcharged – bactual) that Brian must refund to Anna. This will always be an integer.
Sample Input 0
4 1
3 10 2 9
12
Sample Output 0
5
Explanation 0
Anna didn’t eat item bill[1] = 10, but she shared the rest of the items with Brian. The total cost of the shared items is 3 + 2 + 9 = 14 and, split in half, the cost per person is bactual = 7. Brian charged her bcharged = 12 for her portion of the bill. We print the amount Anna was overcharged, bcharged – bactual = 12 – 7 = 5, on a new line.
Sample Input 1
4 1
3 10 2 9
7
Sample Output 1
Bon Appetit
Explanation 1
Anna didn’t eat item bill[1] = 10, but she shared the rest of the items with Brian. The total cost of the shared items is 3 + 2 + 9 = 14 and, split in half, the cost per person is bactual = 7. Because bactual = bcharged = 7, we print Bon Appetit on a new line.
HackerRank Bill Division Solution
Bill Division Solution in C
#include<stdio.h>
int main()
{
int n,k;
scanf("%d %d",&n,&k);
int i,a[n];
for(i=0;i<n;i++)
scanf("%d",&a[i]);
int sum = 0;
for(i=0;i<n;i++)
sum += a[i];
int paid;
scanf("%d",&paid);
int toBePaid = sum-a[k];
if((toBePaid)/2==paid)
printf("Bon Appetit\n");
else
printf("%d\n",paid-(toBePaid)/2);
return 0;
}Bill Division Solution in Cpp
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int n, k, sum=0;
cin >> n >> k;
for (int i=0;i<n;i++) {
int a;
cin >> a;
if (i!=k) sum+=a;
}
int l;
cin >> l;
if (sum/2==l) cout << "Bon Appetit" << endl;
else cout << l-sum/2 << endl;
}Bill Division Solution in Java
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int k=sc.nextInt();
int a[]=new int[n];
int sum=0;
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
if(i!=k){
sum+=a[i];
}
}
int num=sc.nextInt();
if(num==sum/2)
System.out.println("Bon Appetit");
else
System.out.println(num-sum/2);
}
}
Bill Division Solution in Python
n, k = map(int, raw_input().split(' '))
c = map(int, raw_input().split(' '))
t = (sum(c) - c[k]) / 2
z = int(raw_input())
if (t == z):
print "Bon Appetit"
else:
print abs(t - z)Bill Division Solution using JavaScript
function processData(input) {
var next = 0;
var Ns = input[next++].split(' ');
var N = parseInt(Ns[0]);
var k = parseInt(Ns[1]);
var sum = 0;
var items = input[next++].split(' ').map(Number);
var charged = input[next++];
for (i = 0; i < items.length; i++) {
if (i != k) {
sum += items[i];
}
}
if ((sum / 2) == charged) {
console.log('Bon Appetit');
} else {
console.log(charged - (sum / 2));
}
}
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});
process.stdin.on("end", function () {
processData(_input.split('\n'));
});Bill Division Solution in Scala
import scala.io._
object Solution {
def main(args: Array[String]) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution
*/ val nk = io.StdIn.readLine.split(" ").map(_.toInt)
val n = nk(0)
val k = nk(1)
val nums = io.StdIn.readLine.split(" ").map(_.toInt)
val actual = io.StdIn.readInt
val ideal = (nums.sum - nums(k))/2
if (actual - ideal == 0) {
println("Bon Appetit")
}
else {
println(actual - ideal)
}
}
}Bill Division Solution in Pascal
{$mode objfpc}
program A;
var
n, k: Integer;
i: Integer;
TotalCharge, AnnaShare, Charge: uInt64;
c: Int64;
begin
ReadLn(n, k);
for i := 0 to N - 1 do
begin
Read(c);
TotalCharge := TotalCharge + 2 * c;
if i <> k then
AnnaShare := AnnaShare + c;
end;
ReadLn(Charge);
if 2 * Charge = AnnaShare then
WriteLn('Bon Appetit')
else
WriteLn(Charge - AnnaShare div 2);
end.Disclaimer: This problem (Bill Division) is generated by HackerRank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.