Id and Ship Codechef Solution

Hello Programmers In this post, you will know how to solve the Id and Ship Codechef Solution.

Id and Ship Codechef Solution
Id and Ship Codechef Solution

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Codechef by yourself. If you find any difficulty after trying several times, then you can look for solutions.

Problem

Write a program that takes in a letter class ID of a ship and display the equivalent string class description of the given ID. Use the table below.

Class ID Ship Class

B or b BattleShip

C or c Cruiser

D or d Destroyer

F or f Frigate

Input

The first line contains an integer T, the total number of testcases. Then T lines follow, each line contains a character.

Output

For each test case, display the Ship Class depending on ID, in a new line.

Constraints

  • 1 <= T <= 1000

Example

Input:

3
B
c
D

Output:

BattleShip
Cruiser
Destroyer

Id and Ship CodeChef Solutions in Python

T = int(input())
for i in range(T):
    n = input()
    if (n =="B" or n == "b"):
        print("BattleShip")
    elif (n == "C" or n == "c"):
        print("Cruiser")
    elif (n == "D" or n == "d"):
        print("Destroyer")
    else:
        print("Frigate")

Id and Ship CodeChef Solutions in CPP

#include <cctype>
#include <iostream>
#include <cstring>
#include <cstdio>
using namespace::std;
int main(int argc, const char * argv[]) {
    int t;
    cin >> t;
    while (t--) {
        char n;
        cin >> n;
        n = toupper(n);
        switch (n) {
            case 'B':
                cout << "BattleShip" << endl;
                break;
            case 'C':
                cout << "Cruiser" << endl;
                break;
            case 'D':
                cout << "Destroyer" << endl;
                break;
            default:
                cout << "Frigate" << endl;
                break;
        }
    }
    return 0;
}

Id and Ship CodeChef Solutions in JAVA

import java.util.Scanner;
public class Main{
    public static void main(String[] args) {
        Scanner input =new Scanner(System.in);
        int t=input.nextInt();
        char ch;
        while(t-->0)
        {
            ch=input.next().charAt(0);
            if(ch=='B' || ch=='b')
                System.out.println("BattleShip");
            else if(ch=='C' || ch=='c')
                System.out.println("Cruiser");
            else if (ch=='D' || ch=='d')
                System.out.println("Destroyer");
            else if(ch=='F' || ch=='f')
                System.out.println("Frigate");
        }
    }
}
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Disclaimer: The above Problem (Id and Ship) is generated by CodeChef but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purpose.

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