In this post, you will know how to solve the Insert Interval Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.Insert Interval Leetcode SolutionsOne more thing to add, don’t directly look for the solutions, first try to solve the problems of Leetcode by yourself. If you find any difficulty after trying several times, then you can look for solutions.ProblemYou are given an array of non-overlapping intervals intervals where intervals[i] = [starti, endi] represent the start and the end of the ith interval and intervals is sorted in ascending order by starti. You are also given an interval newInterval = [start, end] that represents the start and end of another interval.Insert newInterval into intervals such that intervals is still sorted in ascending order by starti and intervals still does not have any overlapping intervals (merge overlapping intervals if necessary).Return intervals after the insertion.Example 1:Input: intervals = [[1,3],[6,9]], newInterval = [2,5] Output: [[1,5],[6,9]] Example 2:Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8] Output: [[1,2],[3,10],[12,16]] Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10]. Constraints:0 <= intervals.length <= 104intervals[i].length == 20 <= starti <= endi <= 105intervals is sorted by starti in ascending order.newInterval.length == 20 <= start <= end <= 105Insert Interval Leetcode Solutions in Pythonclass Solution: def insert(self, intervals: List[List[int]], newInterval: List[int]) -> List[List[int]]: n = len(intervals) ans = [] i = 0 while i < n and intervals[i][1] < newInterval[0]: ans.append(intervals[i]) i += 1 while i < n and intervals[i][0] <= newInterval[1]: newInterval[0] = min(newInterval[0], intervals[i][0]) newInterval[1] = max(newInterval[1], intervals[i][1]) i += 1 ans.append(newInterval) while i < n: ans.append(intervals[i]) i += 1 return ans Insert Interval Leetcode Solutions in CPPclass Solution { public: vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) { const int n = intervals.size(); vector<vector<int>> ans; int i = 0; while (i < n && intervals[i][1] < newInterval[0]) ans.push_back(intervals[i++]); // Merge overlapping intervals while (i < n && intervals[i][0] <= newInterval[1]) { newInterval[0] = min(newInterval[0], intervals[i][0]); newInterval[1] = max(newInterval[1], intervals[i][1]); ++i; } ans.push_back(newInterval); while (i < n) ans.push_back(intervals[i++]); return ans; } }; Insert Interval Leetcode Solutions in Javaclass Solution { public int[][] insert(int[][] intervals, int[] newInterval) { final int n = intervals.length; List<int[]> ans = new ArrayList<>(); int i = 0; while (i < n && intervals[i][1] < newInterval[0]) ans.add(intervals[i++]); while (i < n && intervals[i][0] <= newInterval[1]) { newInterval[0] = Math.min(newInterval[0], intervals[i][0]); newInterval[1] = Math.max(newInterval[1], intervals[i][1]); ++i; } ans.add(newInterval); while (i < n) ans.add(intervals[i++]); return ans.toArray(new int[ans.size()][]); } } Note: This problem Insert Interval is generated by Leetcode but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.Next: Unique Paths II Leetcode Solution Post navigationPlus One Leetcode Solution Unique Paths II Leetcode Solution