Java Iterator HackerRank Solution

Hello Programmers, In this post, you will know how to solve the Java Iterator HackerRank Solution. This problem is a part of the HackerRank Java Programming Series.

Java Iterator HackerRank Solution
Java Iterator HackerRank Solutions

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

Java Iterator HackerRank Solution

Problem

Java Iterator class can help you to iterate through every element in a collection. Here is a simple example:

import java.util.*;
public class Example{
    public static void main(String []args){
        ArrayList mylist = new ArrayList();
        mylist.add("Hello");
        mylist.add("Java");
        mylist.add("4");
        Iterator it = mylist.iterator();
        while(it.hasNext()){
            Object element = it.next();
            System.out.println((String)element);
        }
    }
}

In this problem you need to complete a method func. The method takes an ArrayList as input. In that ArrayList there is one or more integer numbers, then there is a special string “###”, after that there are one or more other strings. A sample ArrayList may look like this:

element[0]=>42
 element[1]=>10
 element[2]=>"###"
 element[3]=>"Hello"
 element[4]=>"Java"

You have to modify the func method by editing at most 2 lines so that the code only prints the elements after the special string “###”. For the sample above the output will be:

Hello
 Java

Note: The stdin doesn’t contain the string “###”, it is added in the main method.

To restore the original code in the editor, click the top left icon on the editor and create a new buffer.

Java Iterator HackerRank Solutions

import java.util.*;
public class Main
{
   static Iterator func(ArrayList mylist)
   {
      Iterator it=mylist.iterator();
      while(it.hasNext())
      {
         Object element = it.next();
         if(element instanceof String)
            break;
      }
      return it;
   }
   public static void main(String []argh)
   {
      ArrayList mylist = new ArrayList();
      Scanner sc=new Scanner(System.in);
      int n=sc.nextInt();
      int m=sc.nextInt();
      for(int i=0;i<n;i++)
      {
         mylist.add(sc.nextInt());
      }
      mylist.add("###");
      for(int i=0;i<m;i++)
      {
         mylist.add(sc.next());
      }
      Iterator it=func(mylist);
      while(it.hasNext())
      {
         Object element = it.next();
         System.out.println((String)element);
      }
   }
}

Disclaimer: The above Problem (Java Iterator) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

Next: Java Exception Handling Try-catch HackerRank Solution

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