In this post, you will know how to solve the Jump Game Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.Jump Game Leetcode SolutionsOne more thing to add, don’t directly look for the solutions, first try to solve the problems of Leetcode by yourself. If you find any difficulty after trying several times, then you can look for solutions.ProblemYou are given an integer array nums. You are initially positioned at the array’s first index, and each element in the array represents your maximum jump length at that position.Return true if you can reach the last index, or false otherwise.Example 1:Input: nums = [2,3,1,1,4] Output: true Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index. Example 2:Input: nums = [3,2,1,0,4] Output: false Explanation: You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index. Constraints:1 <= nums.length <= 1040 <= nums[i] <= 105Jump Game Leetcode Solutions in Pythonclass Solution: def canJump(self, nums: List[int]) -> bool: i = 0 reach = 0 while i < len(nums) and i <= reach: reach = max(reach, i + nums[i]) i += 1 return i == len(nums) Jump Game Leetcode Solutions in CPPclass Solution { public: bool canJump(vector<int>& nums) { int i = 0; for (int reach = 0; i < nums.size() && i <= reach; ++i) reach = max(reach, i + nums[i]); return i == nums.size(); } }; Jump Game Leetcode Solutions in Javaclass Solution { public boolean canJump(int[] nums) { int i = 0; for (int reach = 0; i < nums.length && i <= reach; ++i) reach = Math.max(reach, i + nums[i]); return i == nums.length; } } Note: This problem Jump Game is generated by Leetcode but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.Next: Minimum Path Sum Leetcode Solution Post navigationCombination Sum Leetcode Solution Minimum Path Sum Leetcode Solution