In this post, you will know how to solve the Pow(x, n) Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.Pow(x, n) Leetcode SolutionOne more thing to add, don’t directly look for the solutions, first try to solve the problems of Leetcode by yourself. If you find any difficulty after trying several times, then you can look for solutions.ProblemImplement pow(x, n), which calculates x raised to the power n (i.e., xn).Example 1:Input: x = 2.00000, n = 10 Output: 1024.00000 Example 2:Input: x = 2.10000, n = 3 Output: 9.26100 Example 3:Input: x = 2.00000, n = -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25 Constraints:-100.0 < x < 100.0-231 <= n <= 231-1n is an integer.-104 <= xn <= 104Pow(x, n) Leetcode Solutions in Pythonclass Solution: def myPow(self, x: float, n: int) -> float: if n == 0: return 1 if n < 0: return 1 / self.myPow(x, -n) if n % 2: return x * self.myPow(x, n - 1) return self.myPow(x * x, n / 2) Pow(x, n) Leetcode Solutions in CPPclass Solution { public: double myPow(double x, long n) { if (n == 0) return 1; if (n < 0) return 1 / myPow(x, -n); if (n & 1) return x * myPow(x, n - 1); return myPow(x * x, n / 2); } }; Pow(x, n) Leetcode Solutions in Javaclass Solution { public double myPow(double x, long n) { if (n == 0) return 1; if (n < 0) return 1 / myPow(x, -n); if (n % 2 == 1) return x * myPow(x, n - 1); return myPow(x * x, n / 2); } } Note: This problem Pow(x, n) is generated by Leetcode but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.NEXT: Maximum Subarray Leetcode Solution Post navigationWildcard Matching Leetcode Solution Maximum Subarray Leetcode Solution